3.2120 \(\int (a+b \sqrt {x})^2 x^4 \, dx\)

Optimal. Leaf size=32 \[ \frac {a^2 x^5}{5}+\frac {4}{11} a b x^{11/2}+\frac {b^2 x^6}{6} \]

[Out]

1/5*a^2*x^5+4/11*a*b*x^(11/2)+1/6*b^2*x^6

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Rubi [A]  time = 0.03, antiderivative size = 32, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {266, 43} \[ \frac {a^2 x^5}{5}+\frac {4}{11} a b x^{11/2}+\frac {b^2 x^6}{6} \]

Antiderivative was successfully verified.

[In]

Int[(a + b*Sqrt[x])^2*x^4,x]

[Out]

(a^2*x^5)/5 + (4*a*b*x^(11/2))/11 + (b^2*x^6)/6

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 266

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rubi steps

\begin {align*} \int \left (a+b \sqrt {x}\right )^2 x^4 \, dx &=2 \operatorname {Subst}\left (\int x^9 (a+b x)^2 \, dx,x,\sqrt {x}\right )\\ &=2 \operatorname {Subst}\left (\int \left (a^2 x^9+2 a b x^{10}+b^2 x^{11}\right ) \, dx,x,\sqrt {x}\right )\\ &=\frac {a^2 x^5}{5}+\frac {4}{11} a b x^{11/2}+\frac {b^2 x^6}{6}\\ \end {align*}

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Mathematica [A]  time = 0.02, size = 28, normalized size = 0.88 \[ \frac {1}{330} x^5 \left (66 a^2+120 a b \sqrt {x}+55 b^2 x\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[(a + b*Sqrt[x])^2*x^4,x]

[Out]

(x^5*(66*a^2 + 120*a*b*Sqrt[x] + 55*b^2*x))/330

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fricas [A]  time = 0.87, size = 24, normalized size = 0.75 \[ \frac {1}{6} \, b^{2} x^{6} + \frac {4}{11} \, a b x^{\frac {11}{2}} + \frac {1}{5} \, a^{2} x^{5} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*(a+b*x^(1/2))^2,x, algorithm="fricas")

[Out]

1/6*b^2*x^6 + 4/11*a*b*x^(11/2) + 1/5*a^2*x^5

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giac [A]  time = 0.15, size = 24, normalized size = 0.75 \[ \frac {1}{6} \, b^{2} x^{6} + \frac {4}{11} \, a b x^{\frac {11}{2}} + \frac {1}{5} \, a^{2} x^{5} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*(a+b*x^(1/2))^2,x, algorithm="giac")

[Out]

1/6*b^2*x^6 + 4/11*a*b*x^(11/2) + 1/5*a^2*x^5

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maple [A]  time = 0.00, size = 25, normalized size = 0.78 \[ \frac {b^{2} x^{6}}{6}+\frac {4 a b \,x^{\frac {11}{2}}}{11}+\frac {a^{2} x^{5}}{5} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^4*(a+b*x^(1/2))^2,x)

[Out]

1/5*a^2*x^5+4/11*a*b*x^(11/2)+1/6*b^2*x^6

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maxima [B]  time = 0.85, size = 166, normalized size = 5.19 \[ \frac {{\left (b \sqrt {x} + a\right )}^{12}}{6 \, b^{10}} - \frac {18 \, {\left (b \sqrt {x} + a\right )}^{11} a}{11 \, b^{10}} + \frac {36 \, {\left (b \sqrt {x} + a\right )}^{10} a^{2}}{5 \, b^{10}} - \frac {56 \, {\left (b \sqrt {x} + a\right )}^{9} a^{3}}{3 \, b^{10}} + \frac {63 \, {\left (b \sqrt {x} + a\right )}^{8} a^{4}}{2 \, b^{10}} - \frac {36 \, {\left (b \sqrt {x} + a\right )}^{7} a^{5}}{b^{10}} + \frac {28 \, {\left (b \sqrt {x} + a\right )}^{6} a^{6}}{b^{10}} - \frac {72 \, {\left (b \sqrt {x} + a\right )}^{5} a^{7}}{5 \, b^{10}} + \frac {9 \, {\left (b \sqrt {x} + a\right )}^{4} a^{8}}{2 \, b^{10}} - \frac {2 \, {\left (b \sqrt {x} + a\right )}^{3} a^{9}}{3 \, b^{10}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*(a+b*x^(1/2))^2,x, algorithm="maxima")

[Out]

1/6*(b*sqrt(x) + a)^12/b^10 - 18/11*(b*sqrt(x) + a)^11*a/b^10 + 36/5*(b*sqrt(x) + a)^10*a^2/b^10 - 56/3*(b*sqr
t(x) + a)^9*a^3/b^10 + 63/2*(b*sqrt(x) + a)^8*a^4/b^10 - 36*(b*sqrt(x) + a)^7*a^5/b^10 + 28*(b*sqrt(x) + a)^6*
a^6/b^10 - 72/5*(b*sqrt(x) + a)^5*a^7/b^10 + 9/2*(b*sqrt(x) + a)^4*a^8/b^10 - 2/3*(b*sqrt(x) + a)^3*a^9/b^10

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mupad [B]  time = 1.10, size = 24, normalized size = 0.75 \[ \frac {a^2\,x^5}{5}+\frac {b^2\,x^6}{6}+\frac {4\,a\,b\,x^{11/2}}{11} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^4*(a + b*x^(1/2))^2,x)

[Out]

(a^2*x^5)/5 + (b^2*x^6)/6 + (4*a*b*x^(11/2))/11

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sympy [A]  time = 1.46, size = 27, normalized size = 0.84 \[ \frac {a^{2} x^{5}}{5} + \frac {4 a b x^{\frac {11}{2}}}{11} + \frac {b^{2} x^{6}}{6} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**4*(a+b*x**(1/2))**2,x)

[Out]

a**2*x**5/5 + 4*a*b*x**(11/2)/11 + b**2*x**6/6

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